I guess you have the wrong number.
If so, there are the following solutions.
Solution:
Let the acceleration of the object motion be a.
There are:
V=aT,VV=2as,V=(2as)^( 1/2),
S=aTT/2,T=(2S/a)^( 1/2)
So:
① After t/2,
The speed is V-aT/2=aT/2=V/2.
The displacement is vt/2-a (t/2) (t/2)/2 = att/2-att/8 = (3/4) (att/2) = (3/4) s.
B correct
(2) After S/2,
The speed is (2as/2) (1/2) = [(2as) (1/2)]/[2 (1/2)] = v/[2 (1/2)].
The time is t-[2 (s/2)/a] (1/2) .................................................. (total time minus the time spent in the second half).
=t-[(2s/a)^( 1/2)]/[2^( 1/2)]
=T-T/[2^( 1/2)]
={ 1-[2^( 1/2)]/2}T
=( 1/2)[2-2^( 1/2)]T
correct
*****
As long as the meaning of the problem is correctly analyzed, then the appropriate formula is used.
You can make the right result.
*****