B is the perpendicular of ray P, which intersects with ray P at D, A is the perpendicular of PD at C, AC=BD, PC=PD+AB=PD+ 10. How much is the top p higher than the top a, that is, PC. Tan 5 1 ≈ 1.2349,Tan 53 ≈ 1.3270。
Tan 53 = PC/AC,Tan 5 1 = PD/BD =(PC- 10)/BD。 From these two equations, PC≈ 144 is obtained.
Therefore, the P peak is higher than the A peak144m. ..